(5x-3)(x+1)=5x^2+1

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Solution for (5x-3)(x+1)=5x^2+1 equation:


Simplifying
(5x + -3)(x + 1) = 5x2 + 1

Reorder the terms:
(-3 + 5x)(x + 1) = 5x2 + 1

Reorder the terms:
(-3 + 5x)(1 + x) = 5x2 + 1

Multiply (-3 + 5x) * (1 + x)
(-3(1 + x) + 5x * (1 + x)) = 5x2 + 1
((1 * -3 + x * -3) + 5x * (1 + x)) = 5x2 + 1
((-3 + -3x) + 5x * (1 + x)) = 5x2 + 1
(-3 + -3x + (1 * 5x + x * 5x)) = 5x2 + 1
(-3 + -3x + (5x + 5x2)) = 5x2 + 1

Combine like terms: -3x + 5x = 2x
(-3 + 2x + 5x2) = 5x2 + 1

Reorder the terms:
-3 + 2x + 5x2 = 1 + 5x2

Add '-5x2' to each side of the equation.
-3 + 2x + 5x2 + -5x2 = 1 + 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
-3 + 2x + 0 = 1 + 5x2 + -5x2
-3 + 2x = 1 + 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
-3 + 2x = 1 + 0
-3 + 2x = 1

Solving
-3 + 2x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2x = 1 + 3

Combine like terms: -3 + 3 = 0
0 + 2x = 1 + 3
2x = 1 + 3

Combine like terms: 1 + 3 = 4
2x = 4

Divide each side by '2'.
x = 2

Simplifying
x = 2

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